SOLUTION: The larger of 2 consecutive integers is eleven more than one-half of the smaller.
Find all of the integers.
Thanks so much in advance!
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Question 342693: The larger of 2 consecutive integers is eleven more than one-half of the smaller.
Find all of the integers.
Thanks so much in advance!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
"The larger of 2 consecutive integers is eleven more than one-half of the smaller.
Find all of the integers." means that where 'x' is the first integer and 'x+1' is the second integer (ie 'x+1' is larger than 'x')
Start with the given equation.
Multiply both sides by the LCD to clear any fractions.
Distribute and multiply.
Subtract from both sides.
Subtract from both sides.
Combine like terms on the left side.
Combine like terms on the right side.
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Answer:
So the solution is
This means that the first integer is 20 and the second integer is 21.
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider making a donation at tutoring website
Jim
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