SOLUTION: Find 3 consecutive integers in which the sum of the first two is 90 more than the last.

Question 341507: Find 3 consecutive integers in which the sum of the first two is 90 more than the last.
Found 2 solutions by edjones, stanbon:
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Let the numbers be x, x+1, x+2.
x+x+1=x+2+90
x=91
.
Ed
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find 3 consecutive integers in which the sum of the first two is 90 more than the last.
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1st: x
2nd: x+1
3rd: x+2
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Equation:
x + x+1 = x+2 + 90
2x+1 = x+92
x = 91
x+1 = 92
x+2 = 93
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Cheers,
Stan H.
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