SOLUTION: If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2800
(C) 4000
(D) 7000
(E) 2
Algebra.Com
Question 340443: If x and y are two-digit integers such that x > 40 and y<70, which of the following is closest to the maximum possible value of xy ?
(A) 700
(B) 2800
(C) 4000
(D) 7000
(E) 28000
Could you please explain the above problem.
Thanks
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The largest two digit number that can be is .
The largest two digit number that can be is .
The product is equal to .
is the closest answer.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If
is a two digit integer that is greater than 40, the largest it could be would be 99. If
is an integer and less than 70, the largest it could be is 69. 69 times 99 is a little bit less than 70 times 100 = 7000.
John

My calculator said it, I believe it, that settles it

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