SOLUTION: Find three consecutive odd integers such that the product of the first and the second exceeds the third by 8. I know the answer is 3, 5, 7, but I need the work. Thanks!

Question 338915: Find three consecutive odd integers such that the product of the first and the second exceeds the third by 8. I know the answer is 3, 5, 7, but I need the work. Thanks!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
"Find three consecutive odd integers such that the product of the first and the second exceeds the third by 8" means that

Start with the given equation.

Combine like terms.

Distribute.

Get every term to the left side.

Combine like terms.

Notice that the quadratic is in the form of where , , and

Let's use the quadratic formula to solve for "x":

Start with the quadratic formula

Plug in , , and

Square to get .

Multiply to get

Rewrite as

Add to to get

Multiply and to get .

Take the square root of to get .

or Break up the expression.

or Combine like terms.

or Simplify.

So the solutions are or

So the three consecutive odd integers are 3, 5, and 7

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website.

Jim
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