SOLUTION: Find two consecutive odd integers such that five times their sum is 23 less than their product. This is how i tried to solve it, but i think that i am missing a step. x(x+2)= 5(x+

SOLUTION: Find two consecutive odd integers such that five times their sum is 23 less than their product. This is how i tried to solve it, but i think that i am missing a step. x(x+2)= 5(x+

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Question 335730: Find two consecutive odd integers such that five times their sum is 23 less than their product. This is how i tried to solve it, but i think that i am missing a step.
x(x+2)= 5(x+x+2)-23
x^2+2x=5x+5x+10-23
x^2+2x=10x-13
x^2-8x-13

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You should have the equation
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