SOLUTION: The product of two consecutive integers is 11 more than their sum. Find the integers. I have tried to solve this but i can't, the way the book explains it is very confusing.
Algebra.Com
Question 335725: The product of two consecutive integers is 11 more than their sum. Find the integers. I have tried to solve this but i can't, the way the book explains it is very confusing.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the first integer be x, then the next consecutive integr is x+1
" The product of two consecutive numbers is 11 more than their sum." Simplify this equation.
Subtract 2x from both sides.
Now subtract 12 from both sides.
Factor this trinomial.
Apply the zero product rule.
or therefore...
or these are the two integers.
Check:
Substitute x = 4.
You can check x = -3 yourself.
RELATED QUESTIONS
the product of two consecutive positive integers is 11 more than their sum. find the... (answered by mananth)
the product of two consecutive integers is 11 more than their sum. find the... (answered by mananth)
The product of two consecutive integers is 8 more than twice their sum. Find the... (answered by Ultimatemagic)
The product of two consecutive integers is 71 more than their sum. Find the... (answered by Earlsdon,fetter6)
The product of two consecutive odd integers is 23 more than their sum. Find the... (answered by Fombitz)
The Product of two consecutive integers is 8 more than twice their sum. Find the... (answered by checkley75,elima)
the product of two consecutive integers is 41 more than their sum. Find the... (answered by EMStelley)
The product of two consecutive integers is 41 more than their sum. Find the... (answered by checkley77)
The product of two consecutive integers is 8 more than twice their sum. Find the... (answered by Stitch)