SOLUTION: find two consecutive odd number such that the sum of their squares is 32 more than twice the square of the smaller number

SOLUTION: find two consecutive odd number such that the sum of their squares is 32 more than twice the square of the smaller number

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Question 334072: find two consecutive odd number such that the sum of their squares is 32 more than twice the square of the smaller number
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the numbers be x and x+2
x^2+(x+2)^2 = 2x^2 +32
x^2+x^2+4x+4=2x^2+32
4x+4=32
4x=32-8
4x=28
x=7
the other number is 9

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