SOLUTION: Less than half the students missed the chemistry demonstration. In fact only 3/10 of the students missed the demonstration. If 21 students did not miss the demonstration, how many

Algebra.Com
Question 333673: Less than half the students missed the chemistry demonstration. In fact only 3/10 of the students missed the demonstration. If 21 students did not miss the demonstration, how many students did miss the demonstration?
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Less than half the students missed the chemistry demonstration.
In fact only 3/10 of the students missed the demonstration.
---
7/10 of the students did not miss the demonstration.
-------------------
If 21 students did not miss the demonstration, how many students did miss the demonstration?
---
Let "x" be the number of students:
Equation:
(7/10)x = 21
(1/10)x = 3
x = 30 students did not miss the demonstration
---
# who missed the demonstration = (3/10)*30 = 9
==============================
Cheers,
Stan H.
=================================================
Cheers,
Stan H.

RELATED QUESTIONS

3. A principal states that in his school, the average number of days per year missed by a (answered by CPhill)
In a class of 100 students, it is known that 45 study mathematics, 26 study chemistry and (answered by richwmiller)
On a test 25% of all students missed a particular question. If 8 people missed the... (answered by ewatrrr)
More than half of the students were excited about the project. In fact, 8/9 were... (answered by Alan3354,ikleyn)
In a class of 100 students, it is known that 45 study mathematics, 26 study chemistry and (answered by Theo)
In a class of 100 students, 40 offer Biology and 10 offer chemistry and Biology. 10 offer (answered by The Troll Kid)
In a class of 60 students, the number of students who passed Biology is 6 more than the... (answered by ikleyn)
Mr. Edge needs 5 students, who will be arranged from tallest to shortest, for a... (answered by stanbon)
Mr. Edge needs 5 students, who will be arranged from tallest to shortest, for a... (answered by ewatrrr)