SOLUTION: One interger is 3 more than twice another. If the product of those integers is 65. find the two integers

Question 333433: One interger is 3 more than twice another. If the product of those integers is 65. find the two integers
Found 2 solutions by Alan3354, ankor@dixie-net.com:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
65 has only 2 factors. Try those.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two integers, x & y
:
"One integer is 3 more than twice another."
x = 2y + 3
;
"If the product of those integers is 65."
x * y = 65
we can also write this:
x =
:
replace x in the 1st equation with
= 2y + 3
Multiply both sides by y
65 = 2y^2 + 3y
a quadratic equation
2y^2 + 3y - 65 = 0
Factors to:
(2y + 13)(y - 5) = 0
:
The integer solution:
y = 5 is one integer
:
find x using the 1st equation:
x = 2(5) + 3
x = 13 is the other integer
:
;
Check 5 * 13 = 65

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