SOLUTION: diff of two no. is 7. their product is 14. sum of their squares is 77. find two no.s?

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Question 332491: diff of two no. is 7. their product is 14. sum of their squares is 77. find two no.s?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
diff of two no. is 7. their product is 14. sum of their squares is 77.
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y-x = 7 --> y=x+7
x*y = 14
Sub for y
x*(x+7) = 14
x^2 + 7x = 14
x^2 + 7x - 14 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=105 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.6234753829798, -8.6234753829798. Here's your graph:

-------------
x = 1.623475
y = 8.623475
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x = -1.623475
y = -8.623475

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