SOLUTION: cannot seem to get this!!! from my teacher's own problem solving packet. it reads... The larger of two consecutive even integers is six less than twice the smaller. Find the numbe

Question 33138: cannot seem to get this!!! from my teacher's own problem solving packet. it reads...
The larger of two consecutive even integers is six less than twice the smaller. Find the numbers.
thank you tons!!!
Found 3 solutions by mukhopadhyay, venugopalramana, sarah_adam:
Answer by mukhopadhyay(490)   (Show Source): You can put this solution on YOUR website!
If one of the even integers is x, the other is x+2;
Per question, (x+2) = 2x-6
=> x = 8;
The numbers are 8 and 10.
Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!
The larger of two consecutive even integers is six less than twice the smaller. Find the numbers.
thank you tons!!!
LET SMALLER EVEN NUMBER BE =2N...
TWICE THIS =2*2N=4N....6 LESS =4N-6...THIS IS EQUAL TO NEXT EVEN NUMBER =2N+2
4N-6=2N+2
4N-2N=2+6=8
2N=8
N=4....SO THE 2 NUMBERS ARE 2*4=8 AND 10.
Answer by sarah_adam(201)   (Show Source): You can put this solution on YOUR website!
The two consequtive even integers are n ,(n+2)
greater integer is (n+2) is six less then twice the smaller one
so (n+2) = 2n - 6
2n - n = 6 +2
n = 8
n+2 = 10
the two integers are 8,10
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