SOLUTION: The tens digit of a two-digit number is 5 more than the units digit. If 3 is subtracted from the number and 2 is added to the reversed number, the former will be twice the latter.
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Question 321402: The tens digit of a two-digit number is 5 more than the units digit. If 3 is subtracted from the number and 2 is added to the reversed number, the former will be twice the latter. What is the number? Is it 2[10(x+5)+ x - 3] = 2 + 10(x)
+ x + 5? How is it written? Thank you.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
the number is 10t + u
t = u + 5
10t + u - 3 = 2(10u + t + 2) ___ 10t + u - 3 = 20u + 2t + 4 ___ 8t = 19u + 7
substituting ___ 8(u + 5) = 19u + 7 ___ 33 = 11u ___ 3 = u
substituting ___ t = (3) + 5 = 8
the number is 83
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