SOLUTION: The number 2002 is equal to the sum of 7 consecutive natural numbers. What is the
smallest of these 7 numbers?
Algebra.Com
Question 321148: The number 2002 is equal to the sum of 7 consecutive natural numbers. What is the
smallest of these 7 numbers?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The number 2002 is equal to the sum of 7 consecutive natural numbers. What is the
smallest of these 7 numbers?
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2002/7 = 286, the middle number
--> 283, 284, 285, 286, 287, 288, 289
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