SOLUTION: Can you help please.
The question reads: The number of bacteria present in a culture after t minutes is given as B=10e^kt. If there are 2167 bacteria present after 15 minutes, kin
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Question 31649: Can you help please.
The question reads: The number of bacteria present in a culture after t minutes is given as B=10e^kt. If there are 2167 bacteria present after 15 minutes, kind k.
(A) 0.384
(B) 80.678
(C) 0.359
(D) 5.379
Thanks for your help!
Found 2 solutions by mukhopadhyay, Earlsdon:
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
Based on the question,
2167 = 10e^15k
=> ln(2167) = ln(10) + 15k
=> 15k = ln(2167) - ln(10) = ln(2167/10) = ln(216.7)
=> k = (ln216.7)/15
=> k = .359
Correct answer: C
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for k:
Substitute B = 2167 and t = 15
Divide both sides by 10.
Take the natural log of both sides.
Substitute
Divide both sides by 15.
Round to nearest thousandth.
k = 0.359
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