SOLUTION: find the two digit number which has the sum of the cubes of its digits equal to three times itself?
Algebra.Com
Question 315543: find the two digit number which has the sum of the cubes of its digits equal to three times itself?
Found 2 solutions by jim_thompson5910, CharlesG2:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Hint: Let t=tens digit and u=units digit. So the number is of the form . Now because "the sum of the cubes of its digits equal to three times itself", this means that . From here, simply find the only positive integer solution.
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
find the two digit number which has the sum of the cubes of its digits equal to three times itself?
24 * 3 = 72
2^3=8
4^3=64
8 + 64 = 72
the answer is 24
below is an Excel Table:
10 1 0 1 0.333333333 NO
11 1 1 2 0.666666667 NO
12 1 8 9 3 NO
13 1 27 28 9.333333333 NO
14 1 64 65 21.66666667 NO
15 1 125 126 42 NO
16 1 216 217 72.33333333 NO
17 1 343 344 114.6666667 NO
18 1 512 513 171 NO
19 1 729 730 243.3333333 NO
20 8 0 8 2.666666667 NO
21 8 1 9 3 NO
22 8 8 16 5.333333333 NO
23 8 27 35 11.66666667 NO
24 8 64 72 24 YES
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