SOLUTION: when the smaller of two consecutive integers is added to two times the larger, the result is 32. how do i solve this cuz im not getting the right numbers. im getting decimals and f

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Question 315390: when the smaller of two consecutive integers is added to two times the larger, the result is 32. how do i solve this cuz im not getting the right numbers. im getting decimals and fractions and i dont think thats right
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Consecutive integers are integers that follow one another. For instance, 1, 2, 3 are consecutive integers. So if 'x' is an integer, then x+1 is the next integer making x and x+1 consecutive integers.


So "when the smaller of two consecutive integers is added to two times the larger, the result is 32", this means that x%2B2%28x%2B1%29=32


x%2B2%28x%2B1%29=32 Start with the given equation.


x%2B2x%2B2=32 Distribute.


3x%2B2=32 Combine like terms on the left side.


3x=32-2 Subtract 2 from both sides.


3x=30 Combine like terms on the right side.


x=%2830%29%2F%283%29 Divide both sides by 3 to isolate x.


x=10 Reduce.


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Answer:

So the solution is x=10


This means that the first integer is 10 and the next consecutive integer is 11.


Notice that 10+2*11=10+22=32 which verifies our answer.