SOLUTION: when the smaller of two consecutive integers is added to two times the larger, the result is 32. how do i solve this cuz im not getting the right numbers. im getting decimals and f

Question 315390: when the smaller of two consecutive integers is added to two times the larger, the result is 32. how do i solve this cuz im not getting the right numbers. im getting decimals and fractions and i dont think thats right
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Consecutive integers are integers that follow one another. For instance, 1, 2, 3 are consecutive integers. So if 'x' is an integer, then x+1 is the next integer making x and x+1 consecutive integers.

So "when the smaller of two consecutive integers is added to two times the larger, the result is 32", this means that

Start with the given equation.

Distribute.

Combine like terms on the left side.

Subtract from both sides.

Combine like terms on the right side.

Divide both sides by to isolate .

Reduce.

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Answer:

So the solution is

This means that the first integer is 10 and the next consecutive integer is 11.

Notice that 10+2*11=10+22=32 which verifies our answer.
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