SOLUTION: Three times the first of three consecutive numbers is four more than two times the second. 3x=2(x+1)+4 3x=2(x+2)+4 3x=2(x+3)+4 is this how I would set it up?

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Question 313399: Three times the first of three consecutive numbers is four more than two times the second.
3x=2(x+1)+4
3x=2(x+2)+4
3x=2(x+3)+4 is this how I would set it up?

Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Which equation? You have 3 of them.
One of them is correct.
.
.
.
First, identify your variables.
- first number
- 1st consecutive number, second number
- 2nd consecutive number, third number
.
.
.
3*First=4+2*Second
.
.
.


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