SOLUTION: Find a three digit number such that if the digits at the tens place and the hundreds place are reversed then the number obtained is twenty percent greater than the original number.

Question 312439: Find a three digit number such that if the digits at the tens place and the hundreds place are reversed then the number obtained is twenty percent greater than the original number.
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
Find a three digit number such that if the digits at the tens place and the hundreds place are reversed then the number obtained is twenty percent greater than the original number.
b*100 + a*10 + c = 1.2 * (a*100 + b*10 + c)
100b + 10a + c = 120a + 12b + 1.2c
10a - 120a + 100b - 12b + c - 1.2c = 0
-110a + 88b - 0.2c = 0
110a - 88b + 0.2c = 0 (divided by -1)
set c = 0
try 9 -> 4+5=9, 5+4=9
110(4) - 88(5) = 440 - 440 = 0
x = 1.2 * 450
x = 540
the 3 digit number is 450

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