SOLUTION: Three consecutive intergers are such that the first plus one-half the second plus seven less than twice the third is 2101. What are the integers?

Question 31097: Three consecutive intergers are such that the first plus one-half the second plus seven less than twice the third is 2101. What are the integers?
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
Three consecutive intergers are such that the first plus one-half the second plus seven less than twice the third is 2101. What are the integers? Help!!!
LET THE 3 CONSEUTIVE INTEGERS BE X,X+1,X+2
FIRST NUMBER =X................................1
HALF OF SECOND NUMBER =(X+1)/2...............2
TWICE THE THIRD =2(X+2)=2X+4
SEVEN LESS THAN THIS =2X+4-7=2X-3...........3
SUM OF THESE 3 IS
X+(X+1)/2 +2X-3=2101.....MULTIPLY BY 2 THROUGH OUT
2X+X+1+4X-6=4202
7X=4202-1+6=4207
X=4207/7=601
SO THE INTEGERS ARE X=601,X+1=602,X+2=603.
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