# SOLUTION: 6) Find 3 consecutive intergers such that the sum of their squares is 50. 7) Find 3 consecutive even intergers such that the sum of the squares of the first two less the square

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 Question 295131: 6) Find 3 consecutive intergers such that the sum of their squares is 50. 7) Find 3 consecutive even intergers such that the sum of the squares of the first two less the square of the third equals 20. 8) Find 3 consecutive odd intergers such that the sum of the squares of the second and third exceeds the square of the first by 209. Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!let the integers be x , x+1, x+2 x^2+(x+1)^2 +(x+2)^2=50 x^2+x^2+2x+1 + x^2+4x+4 =50 3x^2+6x+5=50 3x^2+6x-45=0 x^2+2x-15=0 x^2+5x-3x-15=0 x(x+5)-3(x+5)=0 (x+5)(x-3)=0 x=-5 or x=3 the numbers can be -5, -4, -3 OR 3 , 4 , 5 Both the solutions satisfy the equation