SOLUTION: the problem is: a 45ft rope is cut into 3 peices. the 2nd peice must be twice as long as the 1st peice. the 3rd peice must be 9 feet longer than three times the length of the seco

Question 29435: the problem is: a 45ft rope is cut into 3 peices. the 2nd peice must be twice as long as the 1st peice. the 3rd peice must be 9 feet longer than three times the length of the second peice. how long should each peice be?
i have gotten as far as:
1st peice is x
2nd is 2x(x)
3rd is 9+3(2x(x).
so it goes to x+2x(x)+9+3(2x(x))= 45
Im lost from there.
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
Let the first piece be x
LEt the second piece be 2x
Let the third piece be 9+3(2x)

Equation:
(x)+(2x)+(9+6x)=45
Simplfy

9x=36
x=4

2(4)=8
9+3(8)=33

Hence, the first piece is 4ft long the second piece is 8ft long and the third piece is 33ft long.
Paul.

RELATED QUESTIONS
A 25 inch rope is cut into 3 peices such that the middle sized peice is 1 inch longer... (answered by tonyna22)

A 16inch board is to be cut into 3 peices so that the second peice is twice as long as... (answered by richard1234)

A 36 foot pipe is divided into three peices. One peice is twice as long as the shortest... (answered by checkley71)

A 60 ft. pipe is divided into three peices. One peice is twice a long as the shortest... (answered by checkley71,josmiceli)

A 45-foot rope is to be cut into three pieces. The second piece must be twice as long as... (answered by jim_thompson5910,Electrified_Levi)

A 36 inch board is to be cut into three pieces so that the second piece is twice as long... (answered by stanbon)

a rope measures 168 and is cut in three peices and the first peice is one-half bigger... (answered by mananth)

im not quit sure what cat. this question would go under so i tried to find the closes... (answered by LilSkittleMd)

a rope 82cm long is cut into two pieces with one peice 4 more than twice as long as the... (answered by 24HoursTutor.com)