SOLUTION: The sum of three numbers is 14. The sum of twice the first number, is 6 times the second number, and 7 times the third number is 77. The difference between 3 times the first number
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Question 287562: The sum of three numbers is 14. The sum of twice the first number, is 6 times the second number, and 7 times the third number is 77. The difference between 3 times the first number and the second number is 11. Find the three numbers.
Found 2 solutions by Grinnell, richwmiller:
Answer by Grinnell(63) (Show Source): You can put this solution on YOUR website!
PLease word this problem more correctly. It is poorly worded.
Must have clarification before proceeding further.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
a+b+c=14
so far so good
but you didn't copy all of it .
2a+?????=6b
7*c=77 ???
3a-b=11
Something is wrong with this sentence.
"The sum of twice the first number, is 6 times the second number, and 7 times the third number is 77."
if 7c=77 then c=11
and a +b=3
so b=1 or b=2
and a=1 or a=2
but that doesn't fit with 3a-b=11
So something is very wrong
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