SOLUTION: find three consecutive odd positive intergers such that 2 times the sum of all three is 153 less then the product of the first and second intergers
Algebra.Com
Question 286002: find three consecutive odd positive intergers such that 2 times the sum of all three is 153 less then the product of the first and second intergers
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the smallest of the three integers. Then then next odd integer must be 
, and the one after that has to be 
The sum of the three is
Two times the sum is then:
The product of the first and second is:
So, putting it all together:
Standard form:
Solve the factorable quadratic. Exclude the negative root because the problem asks for positive integers.
John
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