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put this solution on YOUR website!You have all the information you need from the question itself.
Let the numbers be x,y.
"One number is two times another."
Then, x=2y ..................... [Statement 1]
Now y is half of x (from statement 1).
Therefore x>y.
"Eight times the smaller is two more than twice the larger number."
Then, 8y = 2x + 2 .....................[Statement 2]
Substituting (x=2y) in the second equation we get,
8y = 2(2y) + 2
8y = 4y + 2
8y - 4y = 2
4y = 2
y = (2/4)
Therefore, y=1/2
x=2y => x=2(1/2) => x=1
Therefore we get,
x=1
y=(1/2)
Solution crosscheck:
Puttting these solved values of x and y in the 2nd equation we get,
8(1/2) = 2(1) + 2
4 = 2 + 2
4 = 4
As Lefthand side (LHS) and Righthand side (RHS) are equal,
solved values of x and y are correct.
Hope this helps,
Best of luck.
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