SOLUTION: the question is find the reciprocals of three consecutive even integers. i think that it is... {{{ 1/(x) + 1/(x+2) + 1/(x+4) }}} then i find the LCD..so my end answer was x

Question 279539: the question is find the reciprocals of three consecutive even integers.
i think that it is...
then i find the LCD..so my end answer was x^6 + 12x + 8
am i right?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the question is find the reciprocals of three consecutive even integers
-------------
1st even: 2x-2
2nd even: 2x
3rd even: 2x+2
-------------------------
Reciprocals:
1st: 1/(2x-2)
2nd: 1/2x
3rd: 1/(2x+2)
-------------------------
Add them.
---
1/(2(x-1)) + 1/2x + 1/2(x+1)
---
lcd = 2x(x^2-1)
----
Rewrite each fraction with the lcd as its denominator:
(x+1)/lcd + (x^2-1)/lcd + (x-1)/lcd
---------------------------------------
Combine the numerators over the lcd:
[x + 1 + x^2-1 + x-1]/lcd
----------------------------
Simplify the numerator:
[x^2 +2x -1]/[x^2-1]
=========================
Cheers,
Stan H.

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