SOLUTION: Find two consecutive even integers such that twice the smaller exceeds the larger by 18. Thank you.

SOLUTION: Find two consecutive even integers such that twice the smaller exceeds the larger by 18. Thank you.

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Question 277433: Find two consecutive even integers such that twice the smaller exceeds the larger by 18. Thank you.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
Let x & x+2 be the 2 consecutive even integers.
2x=(x+2)+18
2x=x+20
2x-x=20
x=20 ans. for the smallest integer.
20+2=22 ans. for the larger integer.
Proof:
2*20=22+18
40=40
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