SOLUTION: 16 decreased by the sum of twice a # and 11
20 multiplied by two fiths of a #
5 added to the difference between the 3 and eight
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Question 276022: 16 decreased by the sum of twice a # and 11
20 multiplied by two fiths of a #
5 added to the difference between the 3 and eight
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
16 decreased by the sum of twice a # and 11
16 - (2x + 11)
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20 multiplied by two fiths of a #
20(2/5)x
=============================
5 added to the difference between the 3 and eight
(3-8) + 5
=============================
Cheers,
Stan H.
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