SOLUTION: find 3 consecutive odd integers such that the square of the first increased by the product of the other two is 224

Question 273778: find 3 consecutive odd integers such that the square of the first increased by the product of the other two is 224
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
find 3 consecutive odd integers such that the square of the first increased by the product of the other two is 224
:
" 3 consecutive odd integers"
x, (x+2), (x+4)
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"such that the square of the first increased by the product of the other two is 224"
x^2 + ((x+2)(x+4)) = 224
FOIL
x^2 + x^2 + 6x + 8 = 224
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2x^2 + 6x + 8 - 224 = 0
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2x^2 + 6x - 216 = 0
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Simplify, divide by 2
x^2 + 3x - 108 = 0
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Factors to
(x+12)(x-9) = 0
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positive solution
x = 9, the 1st odd integer
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Check using the integers, 9, 11, 13
9^2 + 11*13 =
81 = 143 = 224
:
What about the solution x=-12? It satisfies the equation but,it's an even value

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