SOLUTION: A two-digit number is five times the sum of its digits. The digits from left to right name consecutive integers. Find the number.
Algebra.Com
Question 271640: A two-digit number is five times the sum of its digits. The digits from left to right name consecutive integers. Find the number.
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
A two-digit number is five times the sum of its digits. The digits from left to right name consecutive integers. Find the number.
0 solutions
Let x be the tens digit. Then the ones digit is the next consecutive integer or x+1.
The number then is 10*x + 1*(x+1).
So we have:
10*x + 1*(x+1) = 5*((x + (x + 1))
10x + x + 1 = 5*(2x + 1)
11x + 1 = 10x + 5
Solve the above for x and then calculate x+1.
RELATED QUESTIONS
A three digit number with respective digits from left to right of SSS is added to a three (answered by Edwin McCravy)
A two digit number is 4 times the sum of its digits. If 27 is added to that number its... (answered by josmiceli)
A two-digit number is 11 times its units digit. The sum of the digits is 12. Find the... (answered by bucky)
a two digit number is 11 times its units digit. The sum of the digits is 12. find the... (answered by gwendolyn,Alan3354)
A two-digit number is 6 times its single digit. The sum of the digits is 6. Find the... (answered by ewatrrr,josgarithmetic)
Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by amarjeeth123)
Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by josmiceli)
Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by lwsshak3)
Five times the sum of the digits of a two-digit number is 13 less than the original... (answered by MathTherapy)