SOLUTION: andrew can paint the neighbors house 6 times as fast as bailey. The year andrew and bailey worked
together it took them 7 days. how long would it take each to paint the house?
Algebra.Com
Question 270835: andrew can paint the neighbors house 6 times as fast as bailey. The year andrew and bailey worked
together it took them 7 days. how long would it take each to paint the house?
Found 2 solutions by solver91311, josmiceli:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let
represent the number of days it takes Andrew to paint the house. Then
represents the number of days it would take Bailey to paint the same house.
That means that Andrew can paint
of a house in 1 day, and Bailey can paint
of a house in 1 day. Working together they can paint:
of a house in 1 day.
Performing the sum:
That means that working together they can paint the whole house in:
But we are given that they took 7 days to do the whole job last year, so:
So:
Which happens to be the number of days it would take Bailey working alone. And then:
is the number of days it would take Andrew.
John

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let bailey's rate of painting =
which is 1 house in days
Then Andrew's rate would be
, 6 houses in days
To find their rate working together, add
their rates working alone
Multiply both sides by
Bailey could paint the house in 49 days
Andrew could paint the house in
days
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