# SOLUTION: Four houses on one side of a street have addresses that are consecutive odd numbers. Find each address if the sum of these addresses is 23,672. Thank YOU :)

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 Click here to see ALL problems on Numbers Word Problems Question 268543: Four houses on one side of a street have addresses that are consecutive odd numbers. Find each address if the sum of these addresses is 23,672. Thank YOU :)Found 2 solutions by checkley77, Alan3354:Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!Let x, x+2, x+4 & x+6 be the 4 numbers. x+x+2+x+4+x+6=23,672 4x+12=23,672 4x=23,672-12 4x=23,660 x=23,660/4 x=5,915 is the lowest house number. 5,915+2=5,917 is the second house number. 5,915+4=5,919 is the third house number. 5,915+6=5,921 is the largest house number. Proof: 5,915+5,917+5,919+5,921=23,672 23,672=23,672 Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!23672/4 = 5918 which is the center of the 4 numbers --> 5915, 5917, 5919, 5921