SOLUTION: three numbers are in the ratio 2:3:4. if the smallest is 6x - 8, what is their sum?
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Question 266869: three numbers are in the ratio 2:3:4. if the smallest is 6x - 8, what is their sum?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
three numbers are in the ratio 2:3:4. if the smallest is 6x - 8, what is their sum?
Let m = the multiplier
then the 3 numbers: 2m, 3m, 4m
:
Find m using the 1st number
2m = 6x - 8
m =
m = (3x-4) is the multiplier
:
Find the 2nd number
3m = 3(3x-4) = 9x - 12
:
Find the 3rd number
4m = 4(3x-4) = 12x - 16
:
Add the the three numbers
(6x-8) + (9x-12) + (12x-16) = (27x - 36) is the sum
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