SOLUTION: find two consecutive odd integers whose product is 195

Question 258916: find two consecutive odd integers whose product is 195
Found 3 solutions by Greenfinch, stanbon, Alan3354:
Answer by Greenfinch(383)   (Show Source): You can put this solution on YOUR website!
Call the numbers 2n - 1 and therefore 2n+1
(2n-1)(2n+1)= 195
4n^2 - 196 = 0
2n = 14
So numbers are 13 and 15

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
find two consecutive odd integers whose product is 195
===
1st: 2x+1
2nd: 2x+3
-----
Equation:
(2x+1)(2x+3) = 195
4x^2 +8x + 3 = 195
4x^2 + 8x - 192 = 0
4(x^2 + 2x - 48)
(x-6)(x+8) = 0
---
Positive solution:
x = 6
1st: 2x+1 = 13
2nd: 2x+3 = 15
-------------------
Negative solution:
x = -8
1st: 2x+1 = -15
2nd: 2x+3 = -13
======================
Cheers,
Stan H.
======================

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Do these the easy way.
sqrt(195) is about 14.
One number is just below 14, the other above.
--> 13 & 15
-15 & -13 work also.
RELATED QUESTIONS
Find two consecutive odd integers whose product is... (answered by Targetweek,sommersd)
find two consecutive odd integers whose product is... (answered by drk)
Find two consecutive odd integers whose product is... (answered by stanbon)
Find two consecutive positive odd integers whose product is 195... (answered by Alan3354)
Find two consecutive odd numbers whose product is... (answered by oberobic)
Find two consecutive odd whole numbers whose product is... (answered by Alan3354)
Find two consecutive odd whole numbers whose product is... (answered by Alan3354)
The product of two consecutive odd integers is 195. Find the... (answered by Alan3354)
find the consecutive odd integer whose product is... (answered by Alan3354)