SOLUTION: find 3 consecutive integers such that the square root of the first plus the product of the other two is 46.

SOLUTION: find 3 consecutive integers such that the square root of the first plus the product of the other two is 46.

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Question 258804: find 3 consecutive integers such that the square root of the first plus the product of the other two is 46.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The first integer has to be a square so that the square root is an integer.
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We're already over 46 and this function will only increase.
No solution.
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