SOLUTION: find three consecutive numbers where the product of the smaller two numbers is 40 less than the square of the largest number

SOLUTION: find three consecutive numbers where the product of the smaller two numbers is 40 less than the square of the largest number

Algebra.Com

Question 258273: find three consecutive numbers where the product of the smaller two numbers is 40 less than the square of the largest number
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x*(x+1)=-40+(x+2)^2
x=12
13, 14
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