SOLUTION: What amount of each mixture, one 95% alcohol and the other 15% alcohol, must be used to make 10 liters of a mixture which is 45% alcohol. How would you express this problem in a

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 Question 258077: What amount of each mixture, one 95% alcohol and the other 15% alcohol, must be used to make 10 liters of a mixture which is 45% alcohol. How would you express this problem in an equation?Found 2 solutions by scott8148, stanbon:Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!let x="liters of 95%", so 10-x="liters of 15%" (x)(95%) + (10-x)(15%) = (10)(45%) ___ multiply by 100 to clear percentages 95x + 150 - 15x = 450 80x = 300 x = 3.75 10-x = 6.25 Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!What amount of each mixture, one 95% alcohol and the other 15% alcohol, must be used to make 10 liters of a mixture which is 45% alcohol. -------------------------- Equation: alcohol + alcohol = alcohol 0.95x + 0.15(10-x) = 0.45*10 ---- Multiply thru by 100 to get: 95x + 15*10 - 15x = 45*10 80x = 30*10 x = (1/8)30 x = 3.75 liters (amt. of 95% solution in the mixture) 10-3.75 = 6.25 liters (amt. of 15% solution in the mixture) ================================== Cheers, Stan H.