SOLUTION: hi! heres the problem....the sum of 2 positive integers is 10. the difference of their reciporcals is 3 over 8. find both positive numbers. does x=1st positive and x+1=2nd post

Question 25655: hi! heres the problem....the sum of 2 positive integers is 10. the difference of their reciporcals is 3 over 8. find both positive numbers.
does x=1st positive and x+1=2nd postive? wat do i do with the second part of the problem? is there 2 variables?

thanks so much
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Let one of the integers be "x" and the other be "y".
x+y=10
1/x -1/y= 3/8 or 8(y-x)=3xy
Solve by substitution:
x=10-y
8[y-(10-y)]=3(10-y)y
8[2y-10]=30y-3y^2
16y-80=30y-3y^2
3y^2-14y-80=0
(3y+10)(y-8)=0
y=8 is the positive integer solution
So x=2
Cheers,
stan H.

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