# SOLUTION: Polynomial word problems help please! Find three consecutive odd integers if the product of the first and second integer is 7 less than 10 times the third integer.

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 Click here to see ALL problems on Numbers Word Problems Question 256169: Polynomial word problems help please! Find three consecutive odd integers if the product of the first and second integer is 7 less than 10 times the third integer.Found 2 solutions by solver91311, checkley77:Answer by solver91311(16872)   (Show Source): You can put this solution on YOUR website! Let represent the smallest of the three consecutive odd integers. The next larger consecutive odd integer must then be , and the one after that . The product of the first and second must be: . 7 less than 10 times the third must be: So: Solve the easily factorable quadratic. Both roots are valid answers to the question. John Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!LET X, X+2 & X+4 BE THE 3 INTEGERS. X(X+2)=10(X+4)-7 X^2+2X=10X+40-7 X^2+2X-10X-33=0 X^2-8X-33=0 (X-11)(X+3)=0 X-11=0 X=11 ANS. FOR THE SMALLEST INTEGER. 11+2=13 ANS. FOR THE MIDDLE INTEGER. 11+4=15 FOR THE LARGEST INTEGER. PROOF: 11*13=10*15-7 143=150-7 143=143