SOLUTION: Find four consecutive integers such that the sum of the two greatest is 17 less than twice the sum of the two smallest.

SOLUTION: Find four consecutive integers such that the sum of the two greatest is 17 less than twice the sum of the two smallest.

Algebra.Com

Question 254305: Find four consecutive integers such that the sum of the two greatest is 17 less than twice the sum of the two smallest.
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
Let the consecutive integers be: x, x+1, x+2, and x+3.
(x+2) + (x+3) = 2*(x + x + 1)-17
2x+5 = 2(2x+1) - 17
2x + 5 = 4x+ 2 - 17
2x + 5 = 4x - 15
20 = 2x
10 = x
The integers are
10, 11, 12, and 13.
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