x = 1st integer x+1 = 2nd integer x+2 = 3rd integer x+3 = 4th integerSubtract 6 from all three sides Divide through by 4 The only two integers x between 2.5 and 4.5 are 3 and 4 So there are two sets: x = 1st integer = 3 x+1 = 2nd integer = 4 x+2 = 3rd integer = 5 x+3 = 4th integer = 6 sum = 3+4+5+6=18 and x = 1st integer = 4 x+1 = 2nd integer = 5 x+2 = 3rd integer = 6 x+3 = 4th integer = 7 sum = 4+5+6+7=22 Edwin