SOLUTION: The largest of three numbers is 10 more than the smallest. The middle number is the average of the other two. If the sum of the three numbers is 42, what are the three numbers?

Question 251262: The largest of three numbers is 10 more than the smallest. The middle number is the average of the other two. If the sum of the three numbers is 42, what are the three numbers?
Answer by vksarvepalli(154) (Show Source): You can put this solution on YOUR website!
let the three no.s be a,b and c with a being the smallest and c the largest.
now given c=a+10
and b=(a+c)/2 i.e., 2b=a+c
also a+b+c=42 but from above eq. we have a+c=2b
2b+b=42 implies 3b=42
so, b=14
and a+c=28 (as 2b=28)
now from the first point i.e., c=a+10 we have c-a=10 and also from the above one we have c+a=28,
adding them both we get 2c=28+10=38
so c=19
and a=9
and b=14
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