SOLUTION: The perimeter of a rectangle is 30 centimeters, and the area is 54 square centimeters. Find the length and width of the rectangle. [Hint: Let w represent the width; then 15 - w r
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Question 250256: The perimeter of a rectangle is 30 centimeters, and the area is 54 square centimeters. Find the length and width of the rectangle. [Hint: Let w represent the width; then 15 - w represents the length.]
Answer by mathhub(11) (Show Source): You can put this solution on YOUR website!
Let width = w
Therefore lengh = 15 - w
Area = width*length
AMP Parsing Error of [= w(15-w)]: Invalid expression '=w(15-w)': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203.
.
AMP Parsing Error of [= 15w - w^2]: Invalid expression '=15\w-w^2': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203.
.
It is given that area = 54
=>
=>
=>
=>
=>
=> w = 6 or w = 9
Therefore width is 6 and the length is 9
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