SOLUTION: Find a sequence of three intergers with a common difference of three, such that three times the sum of the first two intergers minus five times the largest interger is 61.

SOLUTION: Find a sequence of three intergers with a common difference of three, such that three times the sum of the first two intergers minus five times the largest interger is 61.

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Question 248101: Find a sequence of three intergers with a common difference of three, such that three times the sum of the first two intergers minus five times the largest interger is 61.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Let the integers be x, x+3, x+6
.
3(x+x+3)-5(x+6)=61
6x+9-5x-30=61
x-21=61
x=82
.
Ed
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