SOLUTION: Find two consecutive odd integers such that when the lesser is added to twice the greater, the result is 12 more than the greater integer

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Question 247281: Find two consecutive odd integers such that when the lesser is added to twice the greater, the result is 12 more than the greater integer
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
let n=first integers
and n+2 the second
n+(2(n+2))=12+n+2
n+2n+4=14+n
3n+4=14+n
subtract 4 from both sides
3n=n+10
subtract n from both sides
2n=10
n=5
n+2=7
check
5+2(7)=12+7
19=19
ok



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