SOLUTION: Find three consecutive odd integers such that 3 times the largest is 57 more than twice the smallest
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Question 246134:  Find three consecutive odd integers such that 3 times the largest is 57 more than twice the smallest
 
Answer by checkley77(12844)   (Show Source): You can put this solution on YOUR website!
 LET X, X+2 & X+4 BE THE 3 ODD INTEGERS.
3(X+4)=2X+57
3X+12=2X+57
3X-2X=57-12
X=45 ANS. FOR THE SMALLEST INTEGER.
45+4=49 ANS. FOR THE LARGEST INTEGER.
PROOF:
3*49=2*45+57
147=90+57
147=147 
 
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