SOLUTION: Find four consecutive even integers whose sum is 244

Question 243058: Find four consecutive even integers whose sum is 244
Found 2 solutions by unlockmath, oberobic:
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let's let x be an even integer. The next three would be shown by x+2, x+4 x+6 so now we can add all these to equal 244. Shown with an equation would look like:
x + x+2 + x+4 + x+6 = 244 Combine like terms will be:
4x+12=244 Subtract 12 from both sides will be:
4x=232 Divide each side by 4 will be:
x=58 So now we know the numbers are:
58, 60, 62, 64
Add these up and we got it.
RJ Toftness
www.math-unlock.com
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
You have 4 consecutive numbers: w, x, y & z.
Their sum is 244: w + x + y + z = 244.
Hmmm...
We appear to have four unknowns and only one equation. That cannot be solved.
But there is a strong hint: They're consecutive.
So we can say,
x = w+2
y = x+2
z = y+2
That's better, but we still have too many variables. So, let's try:
x = w+2
y = w+4
z = w+6
Now we have one equation and one unknown:
w + w+2 + w+4 + w+6 = 244
4w + 12 = 244
4w = 232
w = 58
Checking this solution, we have:
58+60+62+64 = 244
Done.
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