SOLUTION: Find 3 consecutive numbers where the product of the smaller two numbers in 19 less than the square of the largest number?

Question 238551: Find 3 consecutive numbers where the product of the smaller two numbers in 19 less than the square of the largest number?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find 3 consecutive numbers
x, (x+1), (x+2)
:
where the product of the smaller two numbers in 19 less than the square of the largest number?
x(x+1) = (x+2)^2 - 19
:
x^2 + x = x^2 + 4x + 4 - 19
:
0 = x^2 - x^2 + 4x - x + 4 - 19
:
0 = 3x - 15
then
3x = 15
x =
x = 5 is the 1st number 6 = 2nd number and 7 the 3rd number
:
Check:
5*6 = 7^2 - 19
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