SOLUTION: twice the lesser of 2 consecutive integers = 12 less than the greater integer 2x = y-12

Question 235771: twice the lesser of 2 consecutive integers = 12 less than the greater integer
2x = y-12
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
What exactly are you trying to do here?
Are you trying to solve for a specific variable?
Consecutive integers can be more generally represented by x, x +1, x + 2,
x + 3, etc where x is any integer.
Let x = the lesser number
Let x + 1 = the greater number
2x = (x + 1) - 12
Can you solve for x now?

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