SOLUTION: Find 2 consecutive #'s such that when you square the smaller number,the result is 8 less than the product of the 2 #'s?

Question 233126: Find 2 consecutive #'s such that when you square the smaller number,the result is 8 less than the product of the 2 #'s?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find 2 consecutive #'s such that when you square the smaller number,the result is 8 less than the product of the 2 #'s?
----------------------------
smaller: x
larger: x+1
--------------------------
Equation:
x^2 = x(x+1)-8
x^2 = x^2+x-8
x = 8 (smaller number)
x+1 = 9 (larger number)
=========================
Cheers,
Stan H.
RELATED QUESTIONS
Find 2 consecutive numbers such that when you square the smaller number, the result is 8... (answered by checkley77)

1. Find two positive integers such that one is three times the other and their product is (answered by ankor@dixie-net.com)

Find two consecutive integers whose product is five less than the square of the smaller... (answered by Fombitz)

Find two consecutive integers whose product is 3 less than the square of the smaller... (answered by ewatrrr)

find three consecutive integers such that the square of the largest is 23 less than the... (answered by josgarithmetic)

Find 2 consecutive odd integers such that the square root of the larger is 4 less that... (answered by richwmiller)

Find three consecutive even numbers such that the 1st number when subtracted from the sum (answered by chibisan)

Find all sets of two consecutive integers such that their product is eight less than ten... (answered by josgarithmetic)

1. The product of two consecutive odd numbers is 10 more than the square of the smaller... (answered by jojo14344)